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If a five digit number is input through the keyboard.Write a .NET program to calculate the sum of its digits (hint: use the modulus operator)

By Ashok Nalam on 24 Jun 2013 | Category: C# | Tagged: .NET number 
Solve the problem in the programming language .NET. If a five digit number is input through the keyboard.Write a program to calculate the sum of its digits (hint: use the modulus operator)
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Today I found one of programming question in the forums that "Solve the problem in the programming language .NET. If a five digit number is input through the keyboard.Write a program to calculate the sum of its digits (hint: use the modulus operator)". So we will see how to sum the 5 digit number using modulus operator(%).

Input is 12345 then the output should be 1+2+3+4+5=15.

Program:

    class SumOf5DigitsProgram
    {
        public static void Main()
        {
            int sum = 0;
            int number = 12345;
            int tempnumber = number;
            while (tempnumber > 0)
            {
                sum += (tempnumber % 10); // adds last digit of tempnumber to sum
                tempnumber /= 10; // divides tempnumber by 10 to cuts the last digit
            }
            Console.Write("Sum of {0} digit is {1}",number,sum);
            Console.Read();
        }
    }

Code Execution Steps:

number : 12345
tempnumber  = 12345
sum = 0

Iteration1 : 12345>0 - True
sum  = 0 + (12345%10) = 0 + 5 = 5
tempnumber = 12345/10 = 1234

Iteration2: 1234>0 - True
sum  = 5 + (1234%10) = 5 + 4 = 9
tempnumber = 1234/10 = 123

Iteration3: 123>0 - True
sum  = 9 + (123%10) = 9 + 3 = 12
tempnumber = 123/10 = 12

Iterration3: 12>0 - True
sum  = 12 + (12%10) = 12 + 2 = 14
tempnumber = 12/10 = 1

Iteration4: 1>0 - True
sum  = 14 + (1%10) = 14 + 1 = 15
tempnumber = 1/10 = 0

Iteration5: 0>0 - False
sum = 15

Output:

Sum of 12345 digit is 15

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